`EMF` of the cell `Zn ZnSO_(4)(a =0.2)||ZnSO_(4)(a_(2))|Zn` is `-0.0088V` at `25^(@)C`. Calculate the value of `a_(2)`.

`EMF` of the cell `Zn ZnSO_(4)(a =0.2)||ZnSO_(4)(a_(2))|Zn` is `-0.008

1.	`EMF` of the cell `Zn ZnSO_(4)(a =0.2)\|\|ZnSO_(4)(a_(2))\|Zn` is `-0.0088V` at `25^(@)C`. Calculate the value of `a_(2)`.
Answer» Correct Answer - `a_(2) = 0.1006M` `E_(cell) = (0.0591)/(2)log.([0.2])/([a_(2)])` `(-0.0088 xx 2)/(0.0591) =- log. ([0.2])/([a_(2)])` `10^(+0.3) = (0.2)/(a_(2))` `a_(2) = 0.1006`

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`EMF` of the cell `Zn ZnSO_(4)(a =0.2)||ZnSO_(4)(a_(2))|Zn` is `-0.0088V` at `25^(@)C`. Calculate the value of `a_(2)`.

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