1.

Empirical formula of a compound is `A_(2)B_(4)`. If its empirical formula weight is half of its vapour density, determine the molecular formula of the compound.A. `A_(4)B_(8)`B. `A_(8)B_(16)`C. `A_(2)B_(4)`D. `A_(3)B_(6)`

Answer» Let the vapour density of compound be x Empirical formula weight = x/2
Molecular formula weight = 2x
`n=("Molecular formula weight")/("Empirical formula weight ")=(2x)/(x/2) = 4`
Molecular formula = `4 xx A_(2)B_(4) = A_(8)B_(16)`


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