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Empirical formula of a compound is `CH_(2)O` and its molecular mass is 90. The molecular formula of the compound isA. `C_(2)H_(4)O_(2)`B. `C_(3)H_(6)O_(3)`C. `C_(4)H_(8)O_(4)`D. `CH_(2)O` |
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Answer» Correct Answer - C E.F. mass `= 12+2xx1+16=30` Mol. Mass = 120 `n = ("Mol. Mass")/("E.F. mass")=(120)/(3)=4` `:.` Mol formula `= (CH_(2)O)_(4) = C_(4)H_(8)O_(4)` |
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