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Empirical formula of compound is `CH_(2)O`.If its molecular weight is 180 then the molecular formula of the compound isA. `C_(3)H_(6)O_(3)`B. `C_(4)H_(8)O_(4)`C. `C_(6)H_(12)O_(6)`D. `C_(5)H_(10)O_(5)` |
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Answer» Correct Answer - C Molecular formula `= ("Empirical formula")_(n)` `n = ("Molecular weight")/("Empirical formula wt.") = (180)/(30) = 6` `= (CH_(2)O)_(6) = C_(6)H_(12)O_(6)`. |
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