Energy gap in a p – n photodiode is 2.8 eV. Can it detect a waveleng

1.	Energy gap in a p – n photodiode is 2.8 eV. Can it detect a wavelength of 6000 nm? Justify your answer.
Answer» Energy of photon E = hc/λ = (6.62 x 10^-34 x 3 x 10⁸)/(6000 x 10^-9 x 1.6 x 10^-19) eV = 2.06eV As E<Eg (2.8eV), so photodiode cannot detect this photon.

Energy gap in a p – n photodiode is 2.8 eV. Can it detect a wavelength of 6000 nm? Justify your answer.

Answer»

Energy of photon E = hc/λ

= (6.62 x 10^-34 x 3 x 10⁸)/(6000 x 10^-9 x 1.6 x 10^-19) eV

= 2.06eV

As E<Eg (2.8eV), so photodiode cannot detect this photon.

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Energy gap in a p – n photodiode is 2.8 eV. Can it detect a wavelength of 6000 nm? Justify your answer.

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