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Energy if an electron in hydrogen atom in ground state is -13.6 eV. What is the energy of the electron in the third excited state? |
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Answer» SOLUTION :`E_1=-13.6eV` `E_3=(-13.6)/(n^(2))` where n=3 `E_3=(-13.6)/(9)=1.511eV` Energy of the electron IIN the THIRD excited state=1.511 eV. |
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