1.

Energy of an electron in hydrogen atom in ground state is –13.6 eV. What is the energy of the electron in the third excited state?

Answer»

SOLUTION :`E_1 =- 13.6=EV `
` E_3= ( -13.6 )/( n^2)" where " n=3`
`E_3 = ( -13.6 )/(9)= 1.511 eV `
ENERGYOF THEELECTRON in thethirdexcitedstate= 1.511eV .


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