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Energy of an electron in hydrogen atom in ground state is –13.6 eV. What is the energy of the electron in the third excited state? |
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Answer» SOLUTION :`E_1 =- 13.6=EV ` ` E_3= ( -13.6 )/( n^2)" where " n=3` `E_3 = ( -13.6 )/(9)= 1.511 eV ` ENERGYOF THEELECTRON in thethirdexcitedstate= 1.511eV . |
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