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Energy of an electron in hydrogen atom in ground state is -13.6eV.what is the energy of the electron in the second exited state? |
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Answer» SOLUTION :Energy of an electron in ground state=-13.6eV. `:.` energy of an the second EXCITED state`=E_2`. N=2 `E_2=(-13.6eV)/(n^(2))=-13.6/(2^(2))=(-13.6)/(4)` |
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