Energy of an electron in n^(th) Bohr orbit is given as

1.	Energy of an electron in n^(th) Bohr orbit is given as
Answer» `-(n^(2)H^(2))/(4pi^(2)m ZE^(2))` `-(2n^(2)Z^(2) m E^(4))/(n^(2)h^(2))` `-(2pi Ze^(2))/(nh)` `-(n^(2)h^(2))/(2pi^(2)Z^(2) m e^(4))` Answer :B

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