Energy of an electron in the ground state of the hydrogen atom is-2.18 xx 10^(-18) J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol^(-1).

Energy of an electron in the ground state of the hydrogen atom is-2.18

1.	Energy of an electron in the ground state of the hydrogen atom is-2.18 xx 10^(-18) J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol^(-1).
Answer» Solution :Energy of an electron in the ground STATE of the HYDROGEN atom=`2.18xx10^(-18)J` `HtoH^(+)+e^(-)` Energy required to ionize 1 mol e of hydrogen atoms, we MULTIPLY by the Avogadro constant. `E = 2.18 xx 10^(-18) xx 6.023 xx 10^(23)` = 13.123` xx 10^(5) J mol^(-1)` I.E = +1312 KJ `mol^(-1)`