Energy of an electron in the ground state of the hydrogen atom is -2.18 xx 10^(-18) J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol^(-1).

Energy of an electron in the ground state of the hydrogen atom is -2.1

1.	Energy of an electron in the ground state of the hydrogen atom is -2.18 xx 10^(-18) J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol^(-1).
Answer» Solution :Ionization enthalpy is the amount of energy REQUIRED to removed the ELECTRON from ground state to infinity. Energy of electron ground state ` = -2.18 xx 10^(-18) J` Energy of electron at infinity = 0 Energy required to remove electron ` = - (2.18 ) xx 10^(-18) J = 2.18 xx 10^(-18) J` Amount of energy required to remove 1 mol of electrons from 1 mol of H atom ` = 2.18 xx 10^(-18) J xx 6.022 xx 10^(23) `per mol ` :. `Ionization enthalpy of hydrogen ` = 13.130 xx 10^(5) J " mol "^(-1)` ` = 13.13 xx 10^(5) J " mol "^(-1)` NOTE: Ionisation enthalpy is always POSITIVE.