Energy of an electron in the ground state of the hydrogen atomis -2.18xx10xx10^(-18)J. Calculate the ionisation enthalpy of atomic hydrogen in terms of kJ"mol"^(-1),

Energy of an electron in the ground state of the hydrogen atomis -2.18

1.	Energy of an electron in the ground state of the hydrogen atomis -2.18xx10xx10^(-18)J. Calculate the ionisation enthalpy of atomic hydrogen in terms of kJ"mol"^(-1),
Answer» Solution :Energy of an electron is the GROUND state of the hydrogen atom `=-2.18xx10^(-18)s` `HtoH^(+)+e^(-)` energy REQUIRED to ionize 1 mole of hydrogen atoms, we multiply by the Avagardo constant. `E=2.18xx10^(-18)xx6.023xx10^(23)` `=13.123xx10^(5)"J mol"^(-1)` `J.E=+1312"KJ mol"^(-1)`