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InterviewSolution
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Energy of an electron in the ground state of the hydrogen atom is `-2.18xx10^(-18)J`. Calculate the ionisation enthalpy of atomic hydrogen in terms of `J mol^(-1)`. Hint: Apply the idea of mole concept to derive the answer. |
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Answer» It is given that the energy of an electron in the ground state of the hydrogen atom is `-2.18 xx 10^(-18) J`.Therefore, the energy required to remove that electron from the ground state of hydrogen atom is `2.18 xx 10^(-18) J.` `therefore` Ionization enthalpy of atomic hydrogen `= 2.18 xx 10^(-18) J` Hence, ionization enthalpy of atomic hydrogen in terms of `J "mol"^(-1) = 2.18 xx 10^(-18) xx 6.02 xx 10^(23) J "mol"^(-1)` `= 1.31 xx 10^(6) J "mol"^(-1)` |
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