Energy of an electron in the ground state of the hydrogen atom is -2.1

1.	Energy of an electron in the ground state of the hydrogen atom is -2.18 x 10-18 J. Calculate the ionization enthalpy of atomic hydrogen in terms of kJ mol-1 .
Answer» Energy of an electron in the ground state of the hydrogen atom = -2.18 x 10^-18 J H → H⁺ + e^- Energy required to ionize 1 mole of hydrogen atoms, we multiply by the Avogadro constant. E = 2.18 x 10^-18 x 6.023 x 10²³ = 13.123 x 10⁵ J mol^-1 I.E = +1312 K J mol^-1

Energy of an electron in the ground state of the hydrogen atom is -2.18 x 10-18 J. Calculate the ionization enthalpy of atomic hydrogen in terms of kJ mol-1 .

Answer»

Energy of an electron in the ground state of the hydrogen atom = -2.18 x 10^-18 J

H → H⁺ + e^-

Energy required to ionize 1 mole of hydrogen atoms, we multiply by the Avogadro constant.

E = 2.18 x 10^-18 x 6.023 x 10²³

= 13.123 x 10⁵ J mol^-1

I.E = +1312 K J mol^-1