1.

Energy of an electron is given by E = -2.178 xx 10^(-18) J ((Z^(2))/(n^(2))). Wavelength of light required to excite an electron in a hydrogen atom from level 1 to level 2 will be (h = 6.62 xx 10^(-34) Js and c = 3 xx 10^(8) ms^(-1))

Answer»

`8.500 XX 10^(-7) m`
`1.214 xx 10^(-7) m`
`2.816 xx 10^(-7) m`
`6.500 xx 10^(-7) m`

SOLUTION :`Delta E = (hc)/(lamda) = 2.178 xx 10^(-18) ((1)/(1^(2)) - (1)/(2^(2))) Z^(2)`
`= 2.178 xx 10^(-18) xx (3)/(4) xx 1 (Z = 1 " for " H)`
or `lamda = (hc)/(Delta E) = ((6.62 xx 10^(-34)) (3 xx 10^(8)) xx 4)/(2.178 xx 10^(-18) xx 3)`
`= 1.214 xx 10^(-7) m`


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