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Energy of an emitted photon with wavelength `620 nm` is :A. `1 eV`B. `2 eV`C. `1.5 eV`D. `2.5 eV`

Answer» Correct Answer - B
Energy of asn emitted photon ………
`E_(ev)=(1240 eV-nm)/(lambda_(nm))`
or `E_(ev) = (1240)/(620) = 2eV`


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