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Energy of an emitted photon with wavelength `620 nm` is :A. `1 eV`B. `2 eV`C. `1.5 eV`D. `2.5 eV` |
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Answer» Correct Answer - B Energy of asn emitted photon ……… `E_(ev)=(1240 eV-nm)/(lambda_(nm))` or `E_(ev) = (1240)/(620) = 2eV` |
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