1.

Energy of electron of hydrogen atom in second Bohr orbit is

Answer»

`-5.44 XX 10^(-19) J`
`-5.44 xx 10^(-19) kJ`
`-5.44 xx 10^(-19) ` cal
`-5.44 xx 10^(-19) ` eV

Solution :`E=-(2.172xx10^(-18))/n^2=-(2.172xx10^(-18))/2^2`
`=-5.44xx10^(-19)` J


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