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Energy per unit volume for a capacitor having area A and separation d kept at potential diffeence V is given by : -A. `(1)/(2)epsilon_(0)(V^(2))/(d^(2))`B. `(1)/(2epsilon_(0))(V^(2))/(d^(2))`C. `(1)/(2)CV^(2)`D. `(Q^(2))/(2C)` |
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Answer» Correct Answer - A Energy density `=(1)/(2)epsilon_(0)E^(2)` Since `E=(V)/(d)` Therefore, energy density `=(1)/(2)epsilon_(0)((V^(2))/(d^(2)))` |
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