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Energy per unit volume for a capacitor having area A and separation d kept at potential diffeence V is given by : -A. `(1)/(2)epsilon_(0)(V^(2))/(d^(2))`B. `(1)/(2epsilon_(0))(V^(2))/(d^(2))`C. `(1)/(2)CV^(2)`D. `(Q^(2))/(2C)`

Answer» Correct Answer - A
Energy density `=(1)/(2)epsilon_(0)E^(2)`
Since `E=(V)/(d)`
Therefore, energy density `=(1)/(2)epsilon_(0)((V^(2))/(d^(2)))`


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