Energy required to remove an e-from M shell ofH-atom is 1.51 eV, then

1.	Energy required to remove an e-from M shell ofH-atom is 1.51 eV, then energy of first excitedstate will be :-(1) -1.51 eV(2) +1.51 eV(3) -3.4 eV(4) -13.6 eV
Answer» ANSWER: USING the FORMULA -13.6/ N2 EV -13.6/2^2 = -13.6/4 = -3.4 eV.

Energy required to remove an e-from M shell ofH-atom is 1.51 eV, then energy of first excitedstate will be :-(1) -1.51 eV(2) +1.51 eV(3) -3.4 eV(4) -13.6 eV

Answer»

-13.6/2^2 = -13.6/4

= -3.4 eV.