Energy required to stop the ejection of electrons from Cu-plate 0.27 eV. Calculate the work function (in eV) When radiation of lambda= 235nm strikes the plate.

Energy required to stop the ejection of electrons from Cu-plate 0.27 e

1.	Energy required to stop the ejection of electrons from Cu-plate 0.27 eV. Calculate the work function (in eV) When radiation of lambda= 235nm strikes the plate.
Answer» Solution :`E_("photon") =` WORK function +`1/2 mv^2` =work function +`underset("STOPPING POTENTIAL")underset(to)(eV_0)"` ….(i) `E_("Photon") = (hc)/(lambda) = (6.625xx10^(-34) XX 3xx10^8)/(235 xx 10^(-9)) = 5.27 eV` from equation (i) `E_("photon") = W_0 + 0.27` `impliesW_0 = E_("Photon") - 0.27 = 5eV`