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Energy stored in a condenser of capacity `10 uF`, charged to 6kV is used to lift mass of 10 gm. The height to which the body can be raised is (Take `g=10m//s^(2))`A. 180 mB. 18 mC. 1.8 mD. 1800 m |
Answer» Correct Answer - D `C=10muF,V=6kV,m=10gm,h=?` `E=1/2CV^(2)=mgh` `therefore" "h=(CV^(2))/(2mg)=(10xx10^(-6)xx36xx10^(6))/(2xx10xx10xx10^(-3)xx9.8)=1800m` |
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