Enthalpies of formation of CO(g), N_(2)O(g) and N_(2)O_(4)(g) are-110, -393, 81 and 9.7 kJ mol^(-1) respectively . Find the value of Delta_(r)H for the reaction: N_(2)O_(4)(g)+3CO(g) rarr N_(2)O(g) +3CO_(2)(g)

Enthalpies of formation of CO(g), N_(2)O(g) and N_(2)O_(4)(g) are-110,

1.	Enthalpies of formation of CO(g), N_(2)O(g) and N_(2)O_(4)(g) are-110, -393, 81 and 9.7 kJ mol^(-1) respectively . Find the value of Delta_(r)H for the reaction: N_(2)O_(4)(g)+3CO(g) rarr N_(2)O(g) +3CO_(2)(g)
Answer» SOLUTION :`Delta_(r)H = Sigma Delta_(F)H(`Products) `-Sigma Delta_(f)H(` Reactants) `= [ DELTA _(f) H( N_(2)O) +3Delta_(f)H(CO_(2))]- [ Delta_(f)H(N_(2)O_(4)) +3Delta_(f) H(CO)]` `= [8] +3 ( -393)] - [9.7 +3( -110) ] kJ= -777.7 kJ`