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Enthalpy and entropy changes of a reaction are 40.63kJmol^(-1) and 108 J K^(-1) mol^(-1) respectively . Predict the feasibility of the reaction at 27^(@)C

Answer»

Solution :Here, we are given `: Delta H =40.63 kJ mol^(-1)= 40630 J mol^(-1) , Delta S = 108 J K^(-1) mol^(-1)`
`T = 27^(@) C = 27 +273 =300K`
`:. Delta G =Delta H = T Delta S = 40630 J mol^(-1) - 300 K xx 108.8 JK^(-1) mol^(-1) = 7990 J mol^(-1)`
Since `Delta G` comes out to be positive ( i.e., ` Delta Ggt 0)` , the reaction is not feasible in the FORWARD DIRECTION.


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