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Enthalpy and Entropy changes of two reactions are given below: Find out whether they are spontaneous or not at 27°C. Justify. 1. ∆H = 26 kJ/mole, ∆S = 8.3 J/K/mole 2. ∆H = -393.4 kJ/mole, ∆S = 6 J/K/mole |
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Answer» 1. ∆G = ∆H -T∆S = 26000 – 300 × 8.3 = 23.510 Since ∆G is positive, the process is non-spontaneous. 2. ∆G = ∆H -T∆S = -393400 – 300 × 6 = -391600 Since ∆G is negative, the process is spontaneous. |
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