1.

Enthalpy change and entropy change of a chemical reaction are -10.5 kJ mol^(-1) and -31.5 JK^(-1) mol^(-1) respectively. Predict whether the reaction is spontaneous or not at 300 K.

Answer»

Solution :`Delta G = Delta H - T Delta S`
Given, `Delta S = -315 JK^(-1) MOL^(-1)` and `Delta H = -10.5 xx 10^(3) J mol^(-1)`
`:. Delta G = -10500 - 300(-31.5) = -1050 J mol^(-1)`
SINCE `Delta G` is negative, the reaction would be spontaneous.


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