1.

Enthalpy change for the reaction , 4H(g) rarr 2H_(2)(g)is-869.6 kJ. The dissociation energy of H-H bondis

Answer»

`+217 .4kJ`
`-434.8 KJ`
`-869.6kJ`
`+ 434.8kJ`

SOLUTION :`2H_(2)(g) rarr 4H(g), DeltaH = +869.6kJ`
or `H_(2)(g)rarr 2H(g), DeltaH= + ( 869.6)/( 2) Kj`
`=434.8 kJ`


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