1.

Enthalpy change for the reaction, 4H(g) to 2H_(2)(g) is -869.6 kJ. The dissociation energy of H - H bond is

Answer»

`434.8 KJ`
`-869.6 kJ`
`+434.8 kJ`
`+217.4 kJ`

Solution :`4H(g) to 2H_(2)(g)DELTAH = -869.6 kJ`
`2H_(2)(g) to 4H(g) DeltaH = 869.6 kJ`
`H_(2)(g) to 2H(g) DeltaH = 44.8 kJ`


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