1.

Enthalpy is equal to

Answer»

<P>`T^(2) [(del(G//T))/(delT)]_(P)`
`-T^(2) [(del(G//T))/(delT)]_(P)`
`T^(2) [(del(G//T))/(delT)]_(V)`
`-T^(2) [(del(G//T))/(delT)]_(V)`

Solution :It can be derived that
`[ ( del(DeltaG//T))/(delT)] = - ( DeltaH)/(T^(2)) ` ( R efertopage)
or `DeltaH= - T^(2)[(del(DeltaG//T))/(delT)]_(P)`
This is ONE of theforms of Gibbs-Helmholtz EQUATION.


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