Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0)-= - 55.84 kJ//mol Under the same conditions how many mL of 0.1M NaOH and 0.05 M H_(2)A (strong diprotic acid) should be mixed for a total volume of 100mL to produce the highest rise in temperature:

Enthalpy of neutralization is defined as the enthalpy change when 1 mo

1.	Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0)-= - 55.84 kJ//mol Under the same conditions how many mL of 0.1M NaOH and 0.05 M H_(2)A (strong diprotic acid) should be mixed for a total volume of 100mL to produce the highest rise in temperature:
Answer» `25: 75` `50 : 50` `75 : 25` `66.66 : 33.33` SOLUTION :For highest rise, max. NEUTRALIZATION `rArr` eq. acid = eq base `rArr 0.05 xx y xx 2 = 0.1 xx X rArr (x)/(y) = (1)/(1)` i.e., `x=y rArr 50 : 50`