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Enthalpy of solution (ΔH) for BaCl2 .2H2O and BaCl2 are 8.8 and –20.6 kJ mol–1 respectively. Calculate the heat of hydration of BaCl2 to BaCl2 .2H2O. |
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Answer» We are given (i) BaCl2 .2H2O (s) + aq → BaCl2 (aq), Δsol ΔH°1 = 8.8 kJ mol–1 (ii) BaCl2 (s) + aq → BaCl2 (aq), Δsol ΔH°2 = – 20.6 kJ mol–1 We aim at BaCl2 (s) + 2H2O → BaCl2 .2H2O (s), Δhyd H° = ? ΔH = ΔH2 – ΔH1 = – 29.4 kJ mol–1 |
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