1.

Enthalpy of solution (ΔH) for BaCl2 .2H2O and BaCl2 are 8.8 and –20.6 kJ mol–1 respectively. Calculate the heat of hydration of BaCl2 to BaCl2 .2H2O.

Answer»

We are given

(i) BaCl2 .2H2O (s) + aq → BaCl2 (aq), Δsol ΔH°1 = 8.8 kJ mol–1

(ii) BaCl2 (s) + aq → BaCl2 (aq), Δsol ΔH°2 = – 20.6 kJ mol–1 

We aim at

BaCl2 (s) + 2H2O → BaCl2 .2H2O (s), Δhyd H° = ? 

ΔH = ΔH2 – ΔH1 = – 29.4 kJ mol–1 



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