Enthalpy of solution of NaCl(s) is+ 4kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1). Lattice enthalpy of NaCl(s) will be "…..............." kJ mol^(-1)

Enthalpy of solution of NaCl(s) is+ 4kJ mol^(-1) and enthalpy of hydra

1.	Enthalpy of solution of NaCl(s) is+ 4kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1). Lattice enthalpy of NaCl(s) will be "…..............." kJ mol^(-1)
Answer» SOLUTION :`+ 788kJ MOL^(-1)( Delta_("sol") H = Delta_("lattice")H + Delta_(HYD) H ) `