1.

Entropy change for reversible phase transition at contant pressur 'P' and temperature 'T' is calculated by the formula DeltaS=(DeltaH)/(T), where DeltaH is the enthalpy change for phase transition. For irreversible phase transitionDeltaS gt (DeltaH)/(T). Cosider a phase transition "Sn(white, s )" iff Sn ("gray, s") DeltaH^(@) at1 atm & 300K=- 2 kJ mol^(-1). The equilibrium temperature at 1 atm is 400 K. Assume C_(p,m)of Sn (white, s) and Sn (gray, s) are equal. DeltaG^(@) for above phase transition at 1 atm and 300 K is

Answer»

`-500 J mol^(-1)`
`-500 kJ mol^(-1)`
`0`
`-100 J mol^(-1)`

SOLUTION :(B)N/A


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