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Entropy change involved in the conversion of1 mole of liquid water at 373 K to vapour at the same temperature will be ____ (DeltaH_"vap"=2.257 kJ g^(-1)) |
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Answer» Solution :`DeltaH_"vap"=2.257 K J G^(-1)` 1 mole of `H_2O`=18 g `therefore DeltaH_"vap"` for a1 mole = `2.257xx18=40.626 k J g^(-1)` . `T_b` =373 K `DeltaS_"vap"=40.626/373=0.1089 "KJ mol"^(-1)` `=0.109 "kJ mol"^(-1)` |
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