Entropy changes for the process H_(2)O(l) to H_(2)O(g) at normal pressure and at 274 K are given below: DeltaS_(system) = -22.13, DeltaS_("surroundings") = +22.05 The process is non - spontaneous because

Entropy changes for the process H_(2)O(l) to H_(2)O(g) at normal pres

1.	Entropy changes for the process H_(2)O(l) to H_(2)O(g) at normal pressure and at 274 K are given below: DeltaS_(system) = -22.13, DeltaS_("surroundings") = +22.05 The process is non - spontaneous because
Answer» `DeltaS_("SYSTEM")` is -ve `DeltaS_("surroundings")` is + ve `Delta_("UNIVERSE")` is -ve `DeltaS_("system") ne DeltaS_("surroundings")` SOLUTION :For a process to be spontaneous `DeltaS_("universe")` must be positive.Here, `DeltaS_("universe") = -22.13 + 22.05 = -0.08 kJ`