1.

Equal charges each of `20 muC` are placed at `x = 0, 2,4,8,16 cm` on X-axis. Find the force experienced by the charge at `x = 2cm`.

Answer» Correct Answer - `1.2xx10^(3) N`
Force on charge at `x = 2cm` due to charge at `x = 0 cm and x = 4cm` are equal and opposite. They cancel.
Net force on charge at `x = 2cm` is resultant of repulsive forces due to two charges at `x = 8 cm and x = 16cm`.
`:. F = (q xx q)/(4pi in_(0)) xx [(1)/((0.08 - 0.02)^(2)) + (1)/((0.16 - 0.02)^(2))]`
`F = 9xx10^(9) (20xx10^(-6))^(2) [(1)/((0.06)^(2)) + (1)/((0.14)^(2))]`
`F = 1.2xx10^(3) N`


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