Equal masses of H_(2)O_(2) and methane have been taken in a container of volume V at temperature 27^(@)C in identical conditions. The ratio of the volumes of gases H_(2) : O_(2) : methane would be

Equal masses of H_(2)O_(2) and methane have been taken in a container

1.	Equal masses of H_(2)O_(2) and methane have been taken in a container of volume V at temperature 27^(@)C in identical conditions. The ratio of the volumes of gases H_(2) : O_(2) : methane would be
Answer» `8:16:1` `16:8:1` `16:1:2` `8:1:2` Solution :Suppose mass of each of `H_(2), O_(2)` and `CH_(4)` TAKEN =w G `w g H_(2)=(w)/(2)"mole",w g O_(2)=(w)/(32)"mole"`, `w g CH_(4)=(w)/(16)"mole"` As under identical conditions, VOLUME are in the ratio of moles. Hence, volume of `H_(2) : O_(2): CH_(4)=(w)/(2) : (w)/(32) : (w)/(16)` `=(1)/(2) : (1)/(32) : (1)/(16)=16 : 1 : 2`