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Equal masses of the two gases A and B are kept in two separate vessels at the same temperature and pressure. If the ratio of the molecular masses of A and B is `2 : 3`, find the ratio of the volumes of the two vessels. |
Answer» Let the molecular masses of the gases A and B be 2M and 3M respectively. Let the volume of the two vessels in which the gases are kept be `V_(1)` and `V_(2)` respectively. According to ideal gas equation , `PV = nRT = (W)/(M) RT` For gas A : `PV_(1) = (W)/(2M) RT` For gas B : `PV_(2) = (W)/(3M) RT` Divide eqn. (i) by eqn (ii), `(PV_(1))/(PV_(2)) = (W)/(2M) xx (3M)/(W) = 3/2` or `(V_(1))/(V_(2)) = 3/2` The volume of the two gases are in the ratio `3 : 2`. |
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