Equal moles of F_(2(g))and Cl_(2(g)) are introduced into a sealed container and heated to temperature T to attain the following equilibria. Cl_(2(g)) + F_(2(g)) hArr 2C//F_((g)) , Kp_(I)= 3.2 , Cl_(2(g)) + 3 F_(2(g)) hArr 2 CIF_(2(g)) , Kp_(2) . If partial pressures of CIF and CIF_(3) at equilibria are 0.2 and 0.04 atm respectively. What is the value of Kp_(2)?

Equal moles of F_(2(g))and Cl_(2(g)) are introduced into a sealed cont

1.	Equal moles of F_(2(g))and Cl_(2(g)) are introduced into a sealed container and heated to temperature T to attain the following equilibria. Cl_(2(g)) + F_(2(g)) hArr 2C//F_((g)) , Kp_(I)= 3.2 , Cl_(2(g)) + 3 F_(2(g)) hArr 2 CIF_(2(g)) , Kp_(2) . If partial pressures of CIF and CIF_(3) at equilibria are 0.2 and 0.04 atm respectively. What is the value of Kp_(2)?
Answer» 14.66 `ATM^(-2)` 1.466 `atm^(-2)` 14.66 `atm^(-2)` 0.1466 `atm^(-2)` Solution : `:. 3.2=((0.2)^(2))/((P-0.12)(P-0.16)) IMPLIES P=0.2535` `:. 0.2535-0.12""0.2535-0.16""0.04` `=0.1335""=0.0935` `Kp_(2)=((0.04)^(2))/((0.1335)(0.0952)^(3))=14.66 atm^(-2)`