Equal moles of hydrogen and oxygen gas are placed ina container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half fo the hydrogen to escape ?

Equal moles of hydrogen and oxygen gas are placed ina container with a

1.	Equal moles of hydrogen and oxygen gas are placed ina container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half fo the hydrogen to escape ?
Answer» `3//8` `1//2` `1//8` `1//4` Solution :Suppose the number of moles of each gas taken =s moles `H_(2)` escaped in TIME `t=(X)/(2)` mole Suppose number of moles of `O_(2)` DIFFUSED in the same time=n TIMES Then `(r_(O_(2)))/(r_(H_(2)))=sqrt((M_(H_(2)))/(M_(O_(2))))` i.e., `(n//t)/((x//2)//t)=sqrt((2)/(32))"or" (2n)/(x)=(1)/(4)" or" n=(1)/(8)x` `:.` Fraction of `O_(2)` escaped`=(1)/(8)`.