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Equal moles of hydrogen and oxygen gas are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half fo the hydrogen to escape ?A. `3//8`B. `1//2`C. `1//8`D. `1//4` |
Answer» Correct Answer - C Suppose the number of moles of each gas taken =s moles `H_(2)` escaped in time `t=(x)/(2)` mole Suppose number of moles of `O_(2)` diffused in the same time=n times Then `(r_(O_(2)))/(r_(H_(2)))=sqrt((M_(H_(2)))/(M_(O_(2))))` i.e., `(n//t)/((x//2)//t)=sqrt((2)/(32))" or " (2n)/(x)=(1)/(4)" or " n=(1)/(8)x` `:.` Fraction of `O_(2)` escaped`=(1)/(8)`. |
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