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Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape ?A. `3//8`B. `1//2`C. `1//8`D. `1//4` |
Answer» Correct Answer - C Let the moles of each gas `= x` Fraction `H_(2)` escaped `= y_(2)x`. `(r_(O_(2)))/(r_(H_(2)))=sqrt((M_(H_(2)))/(M_(O_(2))))=(nO_(2)//t)/(x/2H_(2)//t) = sqrt((2)/(32)) = 1/4` `n_(o_(2)) = 1/4 xx x/2 = x/8` `n_(o_(2)) = (1)/(4) xx x/2 = x/8` `:.` Fraction of `O_(2)` escaped `= 1//8` |
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