Equal volumes of 0.1 M KCl and 0.1 M FeCl_(3) are mixed with no change in volume, which is/are correct?

Equal volumes of 0.1 M KCl and 0.1 M FeCl_(3) are mixed with no change

1.	Equal volumes of 0.1 M KCl and 0.1 M FeCl_(3) are mixed with no change in volume, which is/are correct?
Answer» `[Fe^(+3)]=0.05M` `[K^(+)]=0.05M` `[Cl^(-)]=0.2M` `[Cl^(-)]gt[K^(+)]` SOLUTION :Let volume of 0.1 M KCl and 0.1 `MFeCl_(3)=Vimplies(a),(b)` `[Fe^(+3)]=((0.1xxV))/(2V)=0.05M` C) `[Cl^(-)]=((0.1xxV)+0.1xx3xxV)/(2V)=(0.4)/(2)=0.2` d) `[Cl^(-)]gt[K^(+)]`