Equal volumes of 1M KMnO_4 and 1M K_2Cr_2O_7 solution are allowed to oxidise Fe^(2+) ions to Fe^(3+) ions in acidic medium. The number of moles of Fe^(2+) ions oxidised in the two cases are in the ratio:

Equal volumes of 1M KMnO_4 and 1M K_2Cr_2O_7 solution are allowed to o

1.	Equal volumes of 1M KMnO_4 and 1M K_2Cr_2O_7 solution are allowed to oxidise Fe^(2+) ions to Fe^(3+) ions in acidic medium. The number of moles of Fe^(2+) ions oxidised in the two cases are in the ratio:
Answer» `1:1` `3:1` `5:6` `6:5` Solution :Eq. mass of KMn04 in acidic medium =`("Mol. mass")/5` Eq. mass of `K_2Cr_2O_7` in acidic medium `=("Mol. mass")/56`. Equalvolumesof1M`KMnO_4`and1M `K_2Cr_2O_7`willhavegramequivalentsin the ratio of 5 : 6. Hence, number of GRAM equivalents (moles, as the eq. mass of `FE^(2+)` = mol. mass) of `Fe^(2+)` IONS oxidised in the TWO cases will also be in the ratio of `5 : 6`.