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Equal volumes of monoatomic and diatomic gases a same initial temperature and pressure are mixed.The ratio of specific heats of the mixture (C_(p)//C_(v))will be |
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Answer» Solution :`C_(v)=(3)/(2)RT,C_(P)=(5)/(2)RT` for monoatomic GAS `C_(v)=(5)/(2)RT,C_(P)=(7)/(2)RT` for monoatomic gas THUS for mixture of 1 mole each, `C_(v)=((3)/(2)RT(5)/(2)RT)/(2)` and `C_(p)=((5)/(2)RT(7)/(2)RT)/(2)` Therefore,`C_(p)//C_(v)=(3RT)/(2RT)=1.5` . |
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