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Equal volumes ofM NaOH and 0.3 M KOH are mixed in an experiment. Find the POH and pH of the resulting solution. |
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Answer» Solution :The concentration of HYDROXYL ions in the MIXTURE `N=(V_1N_1 +V_2 N_2)/( V_1 +V_2) = (V xx 0.6xx V xx 0.2 ) / (V +V ) = 0.4mol L^(-1)` POH of the mixture = -LOG(0.4) = 1-log 4 = 1-0.6=0.4. pH of the mixture = 14 -0.4 = 13.6. |
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