1.

Equation of a circle which passes through (3,6) and touches the axes isA. `x^(2)+y^(2)+6x+6y+3=0`B. `x^(2)+y^(2)-6x-6y-9=0`C. `x^(2)+y^(2)-6x-6y+9=0`D. none of these

Answer» Correct Answer - C
The equation of a circle touching the co-ordinate axes is
`(x-a)^(2)+(y-a)^(2)=a^(2)` or, `x^(2)+y^(2)-2ax-2ay+a^(2)=0`
This passes through (3, 6).
`:. 9 + 36 - 6a - 12a + a^(2)=0 rArr a=3, 15`.
Hence, the required circle are
`x^(2)+y^(2)-6x-6y+9=0` or, `x^(2)+y^(2)-30x-30y+225=0`.


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