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Equation of a circle which passes through (3,6) and touches the axes isA. `x^(2)+y^(2)+6x+6y+3=0`B. `x^(2)+y^(2)-6x-6y-9=0`C. `x^(2)+y^(2)-6x-6y+9=0`D. none of these |
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Answer» Correct Answer - C The equation of a circle touching the co-ordinate axes is `(x-a)^(2)+(y-a)^(2)=a^(2)` or, `x^(2)+y^(2)-2ax-2ay+a^(2)=0` This passes through (3, 6). `:. 9 + 36 - 6a - 12a + a^(2)=0 rArr a=3, 15`. Hence, the required circle are `x^(2)+y^(2)-6x-6y+9=0` or, `x^(2)+y^(2)-30x-30y+225=0`. |
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