1.

Equation of a plane progressive wave is given by y = 0.6 sin 2pi (t - (x)/(2)).On reflection from a denser medium its amplitude becomes (2)/(3)of the amplitude of the incident wave. The equation of the reflected wave is ..........

Answer»

`y =0.6 sin 2pi (t + (x)/(2))`
`y =- 0.4 sin 2pi (t + (x)/(2))`
`y =0.4 sin 2pi (t + (x)/(2))`
`y =-0.4 sin 2pi (t + (x)/(2))`

Solution :Here amplitude of incident wave is `a _(i) =0.6 ` UNIT amplitude of reflected wave would be,
`a _(R) = 2/3 a _(i) = 2/3 xx 0.6 =0.4 ` unit
Equation of incident wave,
`y _(i) = 0.6 sin 2pi (t - (x)/(2))` (As per the statement)
`therefore y _(i) =0.6 sin (2pi t -pi x )`
When above wave gets reflected from the surface of DENSER medeium, its phase INCREASES by `pi` rad. Also, x is to be replaced by `(-x).` Hence, equation of reflected wave would be,
`y _(r) = 0.4 sin [ (2pi t + pix )+pi ]`
`=- 0.4 sin (2pi t +pi x )`
`therefore y _(r) =- 0.4 sin {2pi (t + (x)/(2)) }`


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