Equation of circle inscribed in `|x-a| +|y-b| =1` isA. `(x+a)^(2) + (y+b)^(2) =2`B. `(x-a)^(2) +(y-b)^(2) = (1)/(2)`C. `(x-a)^(2) +(y-b)^(2) = (1)/(sqrt(2))`D. `(x-a)^(2) +(y-b)^(2) = 1`

Equation of circle inscribed in `|x-a| +|y-b| =1` isA. `(x+a)^(2) + (y

1.	Equation of circle inscribed in `\|x-a\| +\|y-b\| =1` isA. `(x+a)^(2) + (y+b)^(2) =2`B. `(x-a)^(2) +(y-b)^(2) = (1)/(2)`C. `(x-a)^(2) +(y-b)^(2) = (1)/(sqrt(2))`D. `(x-a)^(2) +(y-b)^(2) = 1`
Answer» Correct Answer - B `\|x -a\| + \|y-b\| =1` is square with center at (a,b) which is the center of circle also. Distance between two parallel sides of square is `sqrt(2)`. `:.` Radius of the required circle `= (1)/(sqrt(2))` Hence, equation of circle is `(x-a)^(2)+(y-b)^(2) =(1)/(2)`

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Equation of circle inscribed in `|x-a| +|y-b| =1` isA. `(x+a)^(2) + (y+b)^(2) =2`B. `(x-a)^(2) +(y-b)^(2) = (1)/(2)`C. `(x-a)^(2) +(y-b)^(2) = (1)/(sqrt(2))`D. `(x-a)^(2) +(y-b)^(2) = 1`

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