InterviewSolution
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Equation of line of projection of the line 3x-y+2z-1=0=x+2y-z=2 on the plane 3x+2y+z=0 is |
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Answer» `(x+1)/11=(y-1)/-9=(z-1)/-15` `3x-y+2z-1=0=x+2y-z-2` is `3x-y+2z-1+lambda(x+2y-z-2)=0` `rArr (3+lambda)x+(-1+2lambda)y+(2-lambda)z+(-1-2lambda)` =0 Since it must be perpendicular to the given plane. `rArr (3+lambda)3+(-1+2lambda(x+2y-z-2)=0` `rArr (3+lambda)x+(-1+2lambda)2+(2-lambda)1=0` `rArr 6lambda-9 rArr lambda=-3//2` `rArr` Plane is `3x-8y+7z+4=0` Now line of projection is line of INTERSECTION of PLANES `3x-8y+7z+4=0` and `3x+2y+z=0` |
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