1.

Equation of the hyperbola with foci (+-2 ,0) and eccentricity 3/2 is

Answer»

`x^2/9-y^(2)/4=-1`
`x^(2)/(20)-y^(2)/(16)=-1`
`x^(2)/4-y^(2)/5=4/9`
`(9x^(2))/(20)-(9Y^(2))/(16)=-1`

Answer :C


Discussion

No Comment Found

Related InterviewSolutions